80=-16t^2+80

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Solution for 80=-16t^2+80 equation: 



80=-16t^2+80

We move all terms to the left:

80-(-16t^2+80)=0

We get rid of parentheses

16t^2-80+80=0

We add all the numbers together, and all the variables

16t^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{32}=0$

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